Cpp int how many bits




















Privacy policy. Skip to main content. This browser is no longer supported. Download Microsoft Edge More info. Contents Exit focus mode. The minimal value is -2 , the maximal one is 2 The unsigned integer type is uint. It takes 4 bytes of memory and allows expressing integers from 0 to 4 The size of the long type is 8 bytes 64 bits. Including this header you got 8 type stdtype::int8, stdtype::int16, stdtype::int32, stdtype::int64, stdtype::uint8, stdtype::uint16, stdtype::uint32, stdtype::uint This is correct, however, you were also right in saying that: char : 1 byte short : 2 bytes int : 4 bytes long : 4 bytes float : 4 bytes double : 8 bytes.

Because 32 bit architectures are still the default and most used, and they have kept these standard sizes since the pre bit days when memory was less available, and for backwards compatibility and standardization it remained the same. Please reference this for more information:. I notice that all the other answers here have focused almost exclusively on integral types, while the questioner also asked about floating-points.

Then double uses double precision I believe that's the source of the name double , and long double may be either double or quadruple precision it's quadruple on my system, but on bit systems it may be double.

I don't know of any compilers that offer half precision floating-points. As you mentioned - it largely depends upon the compiler and the platform. Here is the one for the Microsoft compiler: Data Type Ranges. You can use variables provided by libraries such as OpenGL , Qt , etc. For example, Qt provides qint8 guaranteed to be 8-bit on all platforms supported by Qt , qint16, qint32, qint64, quint8, quint16, quint32, quint64, etc.

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Asked 12 years, 8 months ago. Active 1 year, 4 months ago. Viewed 1. I'm using Visual Studio on a bit architecture. Here is what I get: char : 1 byte short : 2 bytes int : 4 bytes long : 4 bytes float : 4 bytes double: 8 bytes I tried to find, without much success, reliable information stating the sizes of char , short , int , long , double , float and other types I didn't think of under different architectures and compilers.

Improve this question. Jonathan Leffler k gold badges silver badges bronze badges. See: stackoverflow. Why don't they remove all the vague types, and standardize it all to definite bit length types e. Show 1 more comment. Active Oldest Votes. Putting this all together, we are guaranteed that: char , signed char , and unsigned char are at least 8 bits signed short , unsigned short , signed int , and unsigned int are at least 16 bits signed long and unsigned long are at least 32 bits signed long long and unsigned long long are at least 64 bits No guarantee is made about the size of float or double except that double provides at least as much precision as float.

Improve this answer. Community Bot 1 1 1 silver badge. Alex B Alex B Programmer Read the answer point 1 note in parentheses , or the actual standard's wording linked in the answer. C standard accommodates 1's complement architectures, which have different representation from the most widespread 2's complement. Minimum guaranteed ranges will almost always differ from the actual ranges an implementation provides. Alex B you did not mention anything about double in your answer.

Can you please update your answer for floating point variables? Show 25 more comments. At one time, some Unix systems used an ILP64 organization. Creating an enumeration requires the use of the keyword enum. For example, the following code defines an enumeration of colors called colors and the variable c of type color. Finally, c is assigned the value "blue". By default, the value of the first name is 0, the second name has the value 1, and the third has the value 2, and so on.

But you can give a name, a specific value by adding an initializer. For example, in the following enumeration, green will have the value 5.



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